(2x^2-x-1)*(5-x^2)=0

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Solution for (2x^2-x-1)*(5-x^2)=0 equation: 


Simplifying
(2x2 + -1x + -1)(5 + -1x2) = 0

Reorder the terms:
(-1 + -1x + 2x2)(5 + -1x2) = 0

Multiply (-1 + -1x + 2x2) * (5 + -1x2)
(-1(5 + -1x2) + -1x * (5 + -1x2) + 2x2 * (5 + -1x2)) = 0
((5 * -1 + -1x2 * -1) + -1x * (5 + -1x2) + 2x2 * (5 + -1x2)) = 0
((-5 + 1x2) + -1x * (5 + -1x2) + 2x2 * (5 + -1x2)) = 0
(-5 + 1x2 + (5 * -1x + -1x2 * -1x) + 2x2 * (5 + -1x2)) = 0
(-5 + 1x2 + (-5x + 1x3) + 2x2 * (5 + -1x2)) = 0
(-5 + 1x2 + -5x + 1x3 + (5 * 2x2 + -1x2 * 2x2)) = 0
(-5 + 1x2 + -5x + 1x3 + (10x2 + -2x4)) = 0

Reorder the terms:
(-5 + -5x + 1x2 + 10x2 + 1x3 + -2x4) = 0

Combine like terms: 1x2 + 10x2 = 11x2
(-5 + -5x + 11x2 + 1x3 + -2x4) = 0

Solving
-5 + -5x + 11x2 + 1x3 + -2x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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